What is the derivative of-x^2+4x-3 ?

The derivative of-x^2+4x-3 is -2x+4

What is the first derivative of-x^2+4x-3 ?

The first derivative of-x^2+4x-3 is -2x+4

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\frac{d}{d x} (- x^{2} + 4 x - 3)

- 2 x + 4

Solution steps

\frac{d}{d x} (- x^{2} + 4 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= - 2 x + 4 - 0

Simplify

= - 2 x + 4

\frac{d}{d x} (ln (1 + \frac{1}{x ^{2}}))

f (1) = \frac{8}{x} - x x

\int 4 x^{2} + 7 d x

\frac{\partial}{\partial x} (4 x^{2} y^{3} - x z)

n = 1 \sum \infty \frac{1 + n}{3 ^{n}}

What is the derivative of-x^2+4x-3 ?
The derivative of-x^2+4x-3 is -2x+4
What is the first derivative of-x^2+4x-3 ?
The first derivative of-x^2+4x-3 is -2x+4