What is the first derivative of 4-x ?

The first derivative of 4-x is -1

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derivative of 4-x

\frac{d}{d x} (4 - x)

- 1

Solution steps

\frac{d}{d x} (4 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) - \frac{d x}{d x}

\frac{d}{d x} (4) = 0

\frac{d x}{d x} = 1

= 0 - 1

Simplify

= - 1

y^{^{'}} = 2 x y^{3}

\frac{d}{d t} (cos (t) + 1)

\frac{\partial}{\partial x} (A^{3} (\frac{x}{y})^{2} (1 - x))

\frac{d}{d x} (\frac{x ^{2} - 9}{x - 3})

\frac{d}{d x} (e^{x} (- x^{\frac{2}{3}} - \frac{4}{3} x^{- \frac{3}{2}}))