What is the integral of x^2(x^3+2)^4 ?

The integral of x^2(x^3+2)^4 is 1/15 (x^3+2)^5+C

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integral of x^2(x^3+2)^4

\int x^{2} (x^{3} + 2)^{4} d x

\frac{1}{15} (x^{3} + 2)^{5} + C

Solution steps

\int x^{2} (x^{3} + 2)^{4} d x

Apply u-substitution

: \int \frac{u ^{4}}{3} d u

= \int \frac{u ^{4}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{1}{3} \cdot \frac{u ^{5}}{5}

Substitute back

u = x^{3} + 2

= \frac{1}{3} \cdot \frac{( x ^{3} + 2 ) ^{5}}{5}

Simplify

\frac{1}{3} \cdot \frac{( x ^{3} + 2 ) ^{5}}{5} : \frac{1}{15} (x^{3} + 2)^{5}

= \frac{1}{15} (x^{3} + 2)^{5}

Add a constant to the solution

= \frac{1}{15} (x^{3} + 2)^{5} + C

\int_{0}^{1} x (1 - x)^{2} d x

\int t e^{3 t} d t

x \to + (- 2) lim (x^{2} - x + 4)

y^{^{''}} - 6 y^{^{'}} + 9 y = 4 t e^{3 t}

f (x) = ln (9 sin^{2} (x))

What is the integral of x^2(x^3+2)^4 ?
The integral of x^2(x^3+2)^4 is 1/15 (x^3+2)^5+C