What is laplacetransform-3(sin(4(t-(5pi)/4))) ?

The answer to laplacetransform-3(sin(4(t-(5pi)/4))) is (12)/(s^2+16)

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laplacetransform-3(sin(4(t-(5pi)/4)))

laplace transform

- 3 (sin (4 (t - \frac{5 π}{4})))

\frac{12}{s ^{2} + 16}

Solution steps

L {- 3 (sin (4 (t - \frac{5 π}{4})))}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 3 L {sin (4 (t - \frac{5 π}{4}))}

L {sin (4 (t - \frac{5 π}{4}))} : - \frac{4}{s ^{2} + 16}

= - 3 (- \frac{4}{s ^{2} + 16})

Refine

- 3 (- \frac{4}{s ^{2} + 16}) : \frac{12}{s ^{2} + 16}

= \frac{12}{s ^{2} + 16}

\frac{\partial}{\partial x} (\frac{1}{7 + 5 x})

\int (x^{3} + 2)^{2} (3 x^{2}) d x

\int_{0}^{2} - 4 x^{3} x^{2} + 4 d x

\int_{0}^{\frac{1}{2}} x \cdot cos (π x) d x

\frac{d}{d x} (- \frac{2}{( x + 1 ) ^{3}})

What is laplacetransform-3(sin(4(t-(5pi)/4))) ?
The answer to laplacetransform-3(sin(4(t-(5pi)/4))) is (12)/(s^2+16)