What is the integral of \sqrt[7]{x}+\sqrt[8]{x} ?

The integral of \sqrt[7]{x}+\sqrt[8]{x} is 7/8 x^{8/7}+8/9 x^{9/8}+C

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integral of \sqrt[7]{x}+\sqrt[8]{x}

\frac{7}{8} x^{\frac{8}{7}} + \frac{8}{9} x^{\frac{9}{8}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{7}{8} x^{\frac{8}{7}} + \frac{8}{9} x^{\frac{9}{8}}

Add a constant to the solution

= \frac{7}{8} x^{\frac{8}{7}} + \frac{8}{9} x^{\frac{9}{8}} + C

\int \frac{2 x}{cos ^{2} ( 2 x )} d x

f (x) = - x^{2}

y^{^{'}} - 6 y = 5

\int \frac{5 x - 7}{( x ^{2} - x - 2 ) ( x - 3 )} d x

\frac{d}{d x} (6 ln (x) + 11)

What is the integral of \sqrt[7]{x}+\sqrt[8]{x} ?
The integral of \sqrt[7]{x}+\sqrt[8]{x} is 7/8 x^{8/7}+8/9 x^{9/8}+C