What is the integral of (cos(θ)sin(θ)) ?

The integral of (cos(θ)sin(θ)) is (sin^2(θ))/2+C

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integral of (cos(θ)sin(θ))

\int (cos (θ) sin (θ)) d θ

\frac{sin ^{2} ( θ )}{2} + C

Solution steps

\int cos (θ) sin (θ) d θ

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (θ)

= \frac{sin ^{2} ( θ )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( θ )}{2} + C

y = x^{2}, y = 9 x

\frac{d}{d x} (\frac{11}{( 2 x + 1 ) ^{2}})

\int (3 \cdot x + 5)^{11} d x

\int (13 - x) d x

\frac{x ^{2}}{2 + x}

What is the integral of (cos(θ)sin(θ)) ?
The integral of (cos(θ)sin(θ)) is (sin^2(θ))/2+C