What is the derivative of f(x)=2x^3-4 ?

The derivative of f(x)=2x^3-4 is 6x^2

What is the first derivative of f(x)=2x^3-4 ?

The first derivative of f(x)=2x^3-4 is 6x^2

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derivative of

f (x) = 2 x^{3} - 4

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4) = 0

= 6 x^{2} - 0

Simplify

= 6 x^{2}

\frac{d}{d x} (2 x + \frac{6}{x})

\int \frac{x}{2 x + 1} d x

\int \frac{1}{9 + ( x + 1 ) ^{2}} d x

- ln (cos (x))

\int x^{5} x^{3} - 1 d x

What is the derivative of f(x)=2x^3-4 ?
The derivative of f(x)=2x^3-4 is 6x^2
What is the first derivative of f(x)=2x^3-4 ?
The first derivative of f(x)=2x^3-4 is 6x^2