What is (\partial)/(\partial x)(m+2g(m,x)) ?

The answer to (\partial)/(\partial x)(m+2g(m,x)) is 0+2(\partial)/(\partial x)({g}(m,x))

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(\partial)/(\partial x)(m+2g(m,x))

\frac{\partial}{\partial x} (m + 2 g (m, x))

0 + 2 \frac{\partial}{\partial x} (g (m, x))

Solution steps

\frac{\partial}{\partial x} (m + 2 g (m, x))

Treat

m

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (m) + \frac{\partial}{\partial x} (2 g (m, x))

\frac{\partial}{\partial x} (m) = 0

\frac{\partial}{\partial x} (2 g (m, x)) = 2 \frac{\partial}{\partial x} (g (m, x))

= 0 + 2 \frac{\partial}{\partial x} (g (m, x))

\int \frac{4}{4 - x ^{2}} d x

\int sin^{7} (3 x) cos (3 x) d x

\frac{d}{d x} (\frac{1}{4} x - \frac{1}{10})

\int 5 x e^{7 x} d x

f (x) = 2^{60}

What is (\partial)/(\partial x)(m+2g(m,x)) ?
The answer to (\partial)/(\partial x)(m+2g(m,x)) is 0+2(\partial)/(\partial x)({g}(m,x))