What is the derivative of 2tan^2(x) ?

The derivative of 2tan^2(x) is 4sec^2(x)tan(x)

What is the first derivative of 2tan^2(x) ?

The first derivative of 2tan^2(x) is 4sec^2(x)tan(x)

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\frac{d}{d x} (2 tan^{2} (x))

4 sec^{2} (x) tan (x)

Solution steps

\frac{d}{d x} (2 tan^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (tan^{2} (x))

Apply the chain rule:

2 tan (x) \frac{d}{d x} (tan (x))

= 2 tan (x) \frac{d}{d x} (tan (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 2 \cdot 2 tan (x) sec^{2} (x)

Simplify

= 4 sec^{2} (x) tan (x)

\frac{d}{d x} (6 sin (x) cos (x))

\int_{0}^{2} \frac{y}{9 - y ^{2}} d y

\int \frac{( 5 x + 3 )}{x ^{3} - 2 x ^{2} - 3 x} d x

y^{^{'}} = x^{2} \cdot y

x \to 2 + lim (5)

What is the derivative of 2tan^2(x) ?
The derivative of 2tan^2(x) is 4sec^2(x)tan(x)
What is the first derivative of 2tan^2(x) ?
The first derivative of 2tan^2(x) is 4sec^2(x)tan(x)