What is laplacetransform e^{-9t} ?

The answer to laplacetransform e^{-9t} is 1/(s+9)

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laplacetransform e^{-9t}

laplace transform

e^{- 9 t}

\frac{1}{s + 9}

Solution steps

L {e^{- 9 t}}

Use Laplace Transform table:

L {e^{a t}} = \frac{1}{s - a}

L {e^{- 9 t}} = \frac{1}{s + 9}

= \frac{1}{s + 9}

y = 3 + 6 x + 8 x e^{x}

\frac{d}{d x} (\frac{x ^{2}}{5 ( 1 - x )})

h (x) = 8 x^{2} - 6

x^{0.5}

\frac{\partial}{\partial x} (2 x^{2} + 3 y - 20)

What is laplacetransform e^{-9t} ?
The answer to laplacetransform e^{-9t} is 1/(s+9)