What is the d/(dt)(acos(t)+bsin(t)) ?

The d/(dt)(acos(t)+bsin(t)) is -asin(t)+bcos(t)

What is the first d/(dt)(acos(t)+bsin(t)) ?

The first d/(dt)(acos(t)+bsin(t)) is -asin(t)+bcos(t)

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\frac{d}{d t} (a cos (t) + b sin (t))

- a sin (t) + b cos (t)

Solution steps

\frac{d}{d t} (a cos (t) + b sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a cos (t)) + \frac{d}{d t} (b sin (t))

\frac{d}{d t} (a cos (t)) = - a sin (t)

\frac{d}{d t} (b sin (t)) = b cos (t)

= - a sin (t) + b cos (t)

x \to 0 lim (\frac{7 ^{x} - 5 ^{x}}{x})

\frac{\partial}{\partial x} (z - sin (x y))

\int_{0}^{x} \frac{sin ( t )}{t} d t

x \to - 850 lim (- 7 \frac{2}{13})

What is the d/(dt)(acos(t)+bsin(t)) ?
The d/(dt)(acos(t)+bsin(t)) is -asin(t)+bcos(t)
What is the first d/(dt)(acos(t)+bsin(t)) ?
The first d/(dt)(acos(t)+bsin(t)) is -asin(t)+bcos(t)