What is the integral of (e^x)/(e^{2x)+4} ?

The integral of (e^x)/(e^{2x)+4} is 1/2 arctan((e^x)/2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (e^x)/(e^{2x)+4}

\int \frac{e ^{x}}{e ^{2 x} + 4} d x

\frac{1}{2} arctan (\frac{e ^{x}}{2}) + C

Solution steps

\int \frac{e ^{x}}{e ^{2 x} + 4} d x

Apply u-substitution

: \int \frac{1}{u ^{2} + 4} d u

= \int \frac{1}{u ^{2} + 4} d u

Apply Integral Substitution

= \int \frac{1}{2 ( v ^{2} + 1 )} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{v ^{2} + 1} d v

Use the common integral:

\int \frac{1}{v ^{2} + 1} d v = arctan (v)

= \frac{1}{2} arctan (v)

Substitute back

= \frac{1}{2} arctan (\frac{e ^{x}}{2})

Add a constant to the solution

= \frac{1}{2} arctan (\frac{e ^{x}}{2}) + C

y^{^{''}} + 5 y^{^{'}} + 4 y = 0, y (0) = 1, y^{^{'}} (0) = 0

(e^{2 x} - 5 x)^{2}

\int_{- x}^{x} x^{3} d x

\frac{\partial}{\partial θ} (x cos (θ))

\int s 2^{s} d s

What is the integral of (e^x)/(e^{2x)+4} ?
The integral of (e^x)/(e^{2x)+4} is 1/2 arctan((e^x)/2)+C