What is the integral from 0 to 1 of x^{2/3} ?

The integral from 0 to 1 of x^{2/3} is 3/5

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integral from 0 to 1 of x^{2/3}

\int_{0}^{1} x^{\frac{2}{3}} d x

\frac{3}{5}

Decimal Notation

0.6

Solution steps

\int_{0}^{1} x^{\frac{2}{3}} d x

Apply the Power Rule

: [\frac{3}{5} x^{\frac{5}{3}}]_{0}^{1}

= [\frac{3}{5} x^{\frac{5}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{5}

= \frac{3}{5}

\int 5 yz d x

(\frac{x ^{2}}{x - 5})^{^{'}}

x^{7} (x - 10)^{3}

f (x) = 4 x^{3} e^{x} + e^{x} x^{4}

y^{^{'}} + (4 x) y = - 4 x - 9

What is the integral from 0 to 1 of x^{2/3} ?
The integral from 0 to 1 of x^{2/3} is 3/5