What is the derivative of 3x^3-5x ?

The derivative of 3x^3-5x is 9x^2-5

What is the first derivative of 3x^3-5x ?

The first derivative of 3x^3-5x is 9x^2-5

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\frac{d}{d x} (3 x^{3} - 5 x)

9 x^{2} - 5

Solution steps

\frac{d}{d x} (3 x^{3} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (5 x) = 5

= 9 x^{2} - 5

\frac{2}{x ^{2}} + \frac{3}{x ^{3}}

x \to 2 - lim (\frac{x ^{2}}{( x - 2 )})

\int (8 x - 2 x) d x

\frac{d}{d x} (arctan (\frac{1}{x ^{2}}))

\frac{\partial}{\partial x} (8 x^{2} - 16 y^{3})

What is the derivative of 3x^3-5x ?
The derivative of 3x^3-5x is 9x^2-5
What is the first derivative of 3x^3-5x ?
The first derivative of 3x^3-5x is 9x^2-5