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Popular >

integral of 1-t

Solution

\int 1 - t d t

Solution

t - \frac{t ^{2}}{2} + C

Solution steps

\int 1 - t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d t - \int t d t

\int 1 d t = t

\int t d t = \frac{t ^{2}}{2}

= t - \frac{t ^{2}}{2}

Add a constant to the solution

= t - \frac{t ^{2}}{2} + C

Popular Examples

x d y - (y - x) d x = 0

integral from-1 to 1 of (2-|x|)

\int_{- 1}^{1} (2 - ∣ x ∣) d x

integral of 1/(x^{2021)}

\int \frac{1}{x ^{2021}} d x

limit as x approaches 2 of f(x)x

x \to 2 lim (f (x) x)

4y^{''}+2y^'+4y=100

4 y^{^{''}} + 2 y^{^{'}} + 4 y = 100

Frequently Asked Questions (FAQ)

What is the integral of 1-t ?
The integral of 1-t is t-(t^2)/2+C