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Popular >

y^'+2y=2e^x

Solution

y^{^{'}} + 2 y = 2 e^{x}

Solution

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

Solution steps

y^{'} (x) + 2 y = 2 e^{x}

Solve linear ODE:

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=2e^x ?
The solution for y^'+2y=2e^x is y=(2e^x)/3+(c_{1})/(e^{2x)}