What is the sum from n=0 to infinity of 1/(2^n-1) ?

The sum from n=0 to infinity of 1/(2^n-1) is converges

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sum from n=0 to infinity of 1/(2^n-1)

n = 0 \sum \infty \frac{1}{2 ^{n} - 1}

converges

Solution steps

n = 1 \sum \infty \frac{1}{2 ^{n} - 1}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} (z - e^{x y})

ln (\frac{( e ^{x} + 1 )}{e ^{x} - 1})

y^{^{''}} - 6 y^{^{'}} - 7 y = 0, y (2) = - \frac{1}{3}, y^{^{'}} (0) = 0

5 + \frac{7}{x}

\int \frac{sin ( x )}{x} d x

What is the sum from n=0 to infinity of 1/(2^n-1) ?
The sum from n=0 to infinity of 1/(2^n-1) is converges