What is the d/(dt)({p}(t)e^t) ?

The d/(dt)({p}(t)e^t) is d/(dt)({p}(t))e^t+e^t{p}(t)

What is the first d/(dt)({p}(t)e^t) ?

The first d/(dt)({p}(t)e^t) is d/(dt)({p}(t))e^t+e^t{p}(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (p (t) e^{t})

\frac{d}{d t} (p (t)) e^{t} + e^{t} p (t)

Solution steps

\frac{d}{d t} (p (t) e^{t})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = p (t), g = e^{t}

= \frac{d}{d t} (p (t)) e^{t} + \frac{d}{d t} (e^{t}) p (t)

\frac{d}{d t} (e^{t}) = e^{t}

= \frac{d}{d t} (p (t)) e^{t} + e^{t} p (t)

y = 5 + 1 - x, (- 8, 8)

\int_{0}^{12} 2 π y (144 - y^{2}) d y

\int cos (x) sec (x) sin (x) d x

\frac{d}{d x} (1 + x e^{x})

x \to 4 + lim (ln (x - 4))

What is the d/(dt)({p}(t)e^t) ?
The d/(dt)({p}(t)e^t) is d/(dt)({p}(t))e^t+e^t{p}(t)
What is the first d/(dt)({p}(t)e^t) ?
The first d/(dt)({p}(t)e^t) is d/(dt)({p}(t))e^t+e^t{p}(t)