What is the limit as t approaches 1 of sqrt(t+1) ?

The limit as t approaches 1 of sqrt(t+1) is square root of 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as t approaches 1 of sqrt(t+1)

t \to 1 lim (t + 1)

2

Decimal Notation

1.41421 \dots

Solution steps

t \to 1 lim (t + 1)

Plug in the value

t = 1

= 1 + 1

Simplify

= 2

x \to 7 lim ((3 x + 2)^{\frac{2}{3}})

\int_{0}^{1} (1 - x)^{2} x d x

\int (3 x - \frac{2}{x}) d x

\frac{d y}{d x} = 20 x + y - 20

\int_{7}^{\infty} \frac{9}{v ^{2} - v} d v

What is the limit as t approaches 1 of sqrt(t+1) ?
The limit as t approaches 1 of sqrt(t+1) is square root of 2