What is the derivative of y=2ln(2x) ?

The derivative of y=2ln(2x) is 2/x

What is the first derivative of y=2ln(2x) ?

The first derivative of y=2ln(2x) is 2/x

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derivative of

y = 2 ln (2 x)

\frac{2}{x}

Solution steps

\frac{d}{d x} (2 ln (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (2 x))

Apply the chain rule:

\frac{1}{2 x} \frac{d}{d x} (2 x)

= \frac{1}{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 \cdot \frac{1}{2 x} \cdot 2

Simplify

2 \cdot \frac{1}{2 x} \cdot 2 : \frac{2}{x}

= \frac{2}{x}

\int \frac{1}{2} y d y

\frac{\partial}{\partial x} (\frac{1}{x ^{2}})

2 x^{2} y^{^{''}} + x y^{^{'}} - y = 0

y = x^{4} + 3 e^{x}, (0, 3)

\frac{x ^{3} - 3}{x ^{2} + 2}

What is the derivative of y=2ln(2x) ?
The derivative of y=2ln(2x) is 2/x
What is the first derivative of y=2ln(2x) ?
The first derivative of y=2ln(2x) is 2/x