What is the tangent of f(x)=7x-sqrt(x),(4,26) ?

The tangent of f(x)=7x-sqrt(x),(4,26) is y= 27/4 x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=7x-sqrt(x),(4,26)

tangent of

f (x) = 7 x - x, (4, 26)

y = \frac{27}{4} x - 1

Solution steps

Find the slope of

f (x) = 7 x - x : \frac{df ( x )}{d x} = 7 - \frac{1}{2 x}

Compute the slope of

f (x) = 7 x - x

(4, 26) : m = \frac{27}{4}

Find the line with slope m=

\frac{27}{4}

and passing through

(4, 26) : y = \frac{27}{4} x - 1

y = \frac{27}{4} x - 1

f (x) = (\frac{x + 11}{x - 11})^{6}

\int x^{3} e^{4 x^{2}} d x

\frac{d}{d x} (\frac{2 sin ( x )}{sec ( x )})

\frac{2}{( s - 4 ) ^{2}}

f (x) = \frac{7}{x}, 7, at x = 5

What is the tangent of f(x)=7x-sqrt(x),(4,26) ?
The tangent of f(x)=7x-sqrt(x),(4,26) is y= 27/4 x-1