What is the solution for y^'=(y+sqrt(x^2-y^2))/x ?

The solution for y^'=(y+sqrt(x^2-y^2))/x is y=sin(ln(x)+c_{1})x

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y^'=(y+sqrt(x^2-y^2))/x

y^{^{'}} = \frac{y + x ^{2} - y ^{2}}{x}

y = sin (ln (x) + c_{1}) x

Solution steps

y^{'} (x) = \frac{y + x ^{2} - y ^{2}}{x}

Solve using substitution:

y = sin (ln (x) + c_{1}) x

y = sin (ln (x) + c_{1}) x

\int_{- 2.5}^{4.5} x^{3} d x

\frac{d}{d x} (a cos (x))

x \to - 1 lim (5 - 3 x)

y = 5 x + 1

n = 0 \sum \infty (\frac{x}{5})^{n}

What is the solution for y^'=(y+sqrt(x^2-y^2))/x ?
The solution for y^'=(y+sqrt(x^2-y^2))/x is y=sin(ln(x)+c_{1})x