What is the solution for dy=xsqrt(y)dx ?

The solution for dy=xsqrt(y)dx is y=(x^4}{16}+\frac{c_{1}x^2)/4+(c_{1}^2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

dy=xsqrt(y)dx

d y = x y d x

y = \frac{x ^{4}}{16} + \frac{c _{1} x ^{2}}{4} + \frac{c _{1}^{2}}{4}

Solution steps

d y = x y d x

Solve separable ODE:

y = \frac{x ^{4}}{16} + \frac{c _{1} x ^{2}}{4} + \frac{c _{1}^{2}}{4}

y = \frac{x ^{4}}{16} + \frac{c _{1} x ^{2}}{4} + \frac{c _{1}^{2}}{4}

x - 5

\int \frac{8}{( x + 2 ) ( x ^{2} + 4 )} d x

\frac{\partial}{\partial x} (cos (x y) + sin (yz))

\frac{d}{d x} (\frac{8 x}{9 - tan ( x )})

\frac{- 5 x ^{2}}{2 x + 3}

What is the solution for dy=xsqrt(y)dx ?
The solution for dy=xsqrt(y)dx is y=(x^4}{16}+\frac{c_{1}x^2)/4+(c_{1}^2)/4