What is the sum from n=1 to infinity of ((ln(3n)))/n ?

The sum from n=1 to infinity of ((ln(3n)))/n is diverges

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sum from n=1 to infinity of ((ln(3n)))/n

n = 1 \sum \infty \frac{( ln ( 3 n ) )}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{ln ( 3 n )}{n}

Apply Series Integral Test:

diverges

= diverges

(2 x^{3} + 3)^{6}

(2 x - 3)^{6}

x \to 0 + lim (e^{c o t (x)})

\frac{d y}{d x} = \frac{y}{x} + \frac{y ^{2}}{x}

What is the sum from n=1 to infinity of ((ln(3n)))/n ?
The sum from n=1 to infinity of ((ln(3n)))/n is diverges