What is (\partial)/(\partial y)(x^3-xy) ?

The answer to (\partial)/(\partial y)(x^3-xy) is -x

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(\partial)/(\partial y)(x^3-xy)

\frac{\partial}{\partial y} (x^{3} - x y)

- x

Solution steps

\frac{\partial}{\partial y} (x^{3} - x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{3}) - \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x^{3}) = 0

\frac{\partial}{\partial y} (x y) = x

= 0 - x

Simplify

= - x

f (x) = (- 3 x^{2} - 2)^{4}

x \to 0.9 lim (2 (0.9) + 1)

x \to 6 lim (x^{2})

(\frac{3}{10}, - 2), (- \frac{1}{5}, - \frac{1}{5})

x \to 0 lim (\frac{x}{sin ( 9 x )})

What is (\partial)/(\partial y)(x^3-xy) ?
The answer to (\partial)/(\partial y)(x^3-xy) is -x