What is the derivative of e^{2x+y} ?

The derivative of e^{2x+y} is e^{2x+y}(2+(dy)/(dx))

What is the first derivative of e^{2x+y} ?

The first derivative of e^{2x+y} is e^{2x+y}(2+(dy)/(dx))

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\frac{d}{d x} (e^{2 x + y})

e^{2 x + y} (2 + \frac{d y}{d x})

Solution steps

\frac{d}{d x} (e^{2 x + y})

Apply the chain rule:

e^{2 x + y} \frac{d}{d x} (2 x + y)

= e^{2 x + y} \frac{d}{d x} (2 x + y)

\frac{d}{d x} (2 x + y) = 2 + \frac{d y}{d x}

= e^{2 x + y} (2 + \frac{d y}{d x})

\int \frac{- 5 x - 41}{x ^{2} + x - 12} d x

\int (x^{4} - 5 e^{- 2 x}) d x

\frac{d}{d x} ((x^{2} + 4 x - 5)^{3})

\frac{\partial}{\partial x} (x^{2} + 2 y^{2})

x \frac{d y}{d x} + y = x, y (1) = 3

What is the derivative of e^{2x+y} ?
The derivative of e^{2x+y} is e^{2x+y}(2+(dy)/(dx))
What is the first derivative of e^{2x+y} ?
The first derivative of e^{2x+y} is e^{2x+y}(2+(dy)/(dx))