What is the derivative of (x^2+4x-5^3) ?

The derivative of (x^2+4x-5^3) is 3(x^2+4x-5)^2(2x+4)

What is the first derivative of (x^2+4x-5^3) ?

The first derivative of (x^2+4x-5^3) is 3(x^2+4x-5)^2(2x+4)

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\frac{d}{d x} ((x^{2} + 4 x - 5)^{3})

3 (x^{2} + 4 x - 5)^{2} (2 x + 4)

Solution steps

\frac{d}{d x} ((x^{2} + 4 x - 5)^{3})

Apply the chain rule:

3 (x^{2} + 4 x - 5)^{2} \frac{d}{d x} (x^{2} + 4 x - 5)

= 3 (x^{2} + 4 x - 5)^{2} \frac{d}{d x} (x^{2} + 4 x - 5)

\frac{d}{d x} (x^{2} + 4 x - 5) = 2 x + 4

= 3 (x^{2} + 4 x - 5)^{2} (2 x + 4)

\frac{\partial}{\partial x} (x^{2} + 2 y^{2})

x \frac{d y}{d x} + y = x, y (1) = 3

\frac{d}{d t} (e^{t} sin (9 t))

\int_{0}^{\frac{3 π}{2}} cos^{3} (37 x) d x

\int \frac{cos ( x )}{( 1 - sin ( x ) )} d x

What is the derivative of (x^2+4x-5^3) ?
The derivative of (x^2+4x-5^3) is 3(x^2+4x-5)^2(2x+4)
What is the first derivative of (x^2+4x-5^3) ?
The first derivative of (x^2+4x-5^3) is 3(x^2+4x-5)^2(2x+4)