What is the integral of e^{7x+8} ?

The integral of e^{7x+8} is 1/7 e^{7x+8}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{7x+8}

\int e^{7 x + 8} d x

\frac{1}{7} e^{7 x + 8} + C

Solution steps

\int e^{7 x + 8} d x

Apply u-substitution

: \int e^{u} \frac{1}{7} d u

= \int e^{u} \frac{1}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{7} e^{u}

Substitute back

u = 7 x + 8

= \frac{1}{7} e^{7 x + 8}

Add a constant to the solution

= \frac{1}{7} e^{7 x + 8} + C

\int (e^{x} sin (y) - y) d x

ln (tan^{2} (x))

y = x, y = x^{2} - 2, y = 0

x y^{^{'}} - 2 y = x^{4}

n = 0 \sum \infty e^{(2 n - 1)}