What is the integral of (\sqrt[5]{x^2}) ?

The integral of (\sqrt[5]{x^2}) is 5/7 x^{7/5}+C

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integral of (\sqrt[5]{x^2})

\frac{5}{7} x^{\frac{7}{5}} + C

Solution steps

assuming

x \geq 0

= \int x^{\frac{2}{5}} d x

Apply the Power Rule

: \frac{5}{7} x^{\frac{7}{5}}

= \frac{5}{7} x^{\frac{7}{5}}

Add a constant to the solution

= \frac{5}{7} x^{\frac{7}{5}} + C

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What is the integral of (\sqrt[5]{x^2}) ?
The integral of (\sqrt[5]{x^2}) is 5/7 x^{7/5}+C