What is the integral from 0 to 1 of xe^x ?

The integral from 0 to 1 of xe^x is 1

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integral from 0 to 1 of xe^x

\int_{0}^{1} x e^{x} d x

1

Solution steps

\int_{0}^{1} x e^{x} d x

Apply Integration By Parts

: [e^{x} x - \int e^{x} d x]_{0}^{1}

= [e^{x} x - \int e^{x} d x]_{0}^{1}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{0}^{1}

Compute the boundaries:

1

= 1

x y y^{^{'}} = (y^{2} - 1)^{\frac{3}{2}}

\frac{\partial}{\partial y} (x yz + x y^{5} + y z^{5} + z x^{5})

\int_{0}^{1} cos^{2} (2 π x) d x

\frac{d}{d x} (x^{0.5} + 2 x^{- 0.5})

(2.6) (- 3.5)

What is the integral from 0 to 1 of xe^x ?
The integral from 0 to 1 of xe^x is 1