What is the derivative of (2x^5+6)/(x^3) ?

The derivative of (2x^5+6)/(x^3) is (2(2x^5-9))/(x^4)

What is the first derivative of (2x^5+6)/(x^3) ?

The first derivative of (2x^5+6)/(x^3) is (2(2x^5-9))/(x^4)

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derivative of

\frac{2 x ^{5} + 6}{x ^{3}}

\frac{2 ( 2 x ^{5} - 9 )}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{5} + 6}{x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x ^{5} + 6 ) x ^{3} - \frac{d}{d x} ( x ^{3} ) ( 2 x ^{5} + 6 )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (2 x^{5} + 6) = 10 x^{4}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{10 x ^{4} x ^{3} - 3 x ^{2} ( 2 x ^{5} + 6 )}{( x ^{3} ) ^{2}}

Simplify

\frac{10 x ^{4} x ^{3} - 3 x ^{2} ( 2 x ^{5} + 6 )}{( x ^{3} ) ^{2}} : \frac{2 ( 2 x ^{5} - 9 )}{x ^{4}}

= \frac{2 ( 2 x ^{5} - 9 )}{x ^{4}}

x^{2}, x + 2, 2, - 1

\int - 5 x^{5} e^{x^{6}} d x

\int 9 x d x

28 y^{^{''}} - 14 y^{^{'}} = 0, y (- 2) = 3, y^{^{'}} (3) = - 1

\int \frac{1}{e ^{x} - 9 e ^{- x}} d x

What is the derivative of (2x^5+6)/(x^3) ?
The derivative of (2x^5+6)/(x^3) is (2(2x^5-9))/(x^4)
What is the first derivative of (2x^5+6)/(x^3) ?
The first derivative of (2x^5+6)/(x^3) is (2(2x^5-9))/(x^4)