What is the solution for (dy)/(dx)=(x-1)/(x+3)(y-2)/(y-3) ?

The solution for (dy)/(dx)=(x-1)/(x+3)(y-2)/(y-3) is y=-\W(-((x+3)^4)/(e^{-c_{1)+x-2}})+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(x-1)/(x+3)(y-2)/(y-3)

\frac{d y}{d x} = \frac{x - 1}{x + 3} \frac{y - 2}{y - 3}

y = - W (- \frac{( x + 3 ) ^{4}}{e ^{- c_{1} + x - 2}}) + 2

Solution steps

\frac{d y}{d x} = \frac{x - 1}{x + 3} \frac{y - 2}{y - 3}

Solve separable ODE:

y = - W (- \frac{( x + 3 ) ^{4}}{e ^{- c_{1} + x - 2}}) + 2

y = - W (- \frac{( x + 3 ) ^{4}}{e ^{- c_{1} + x - 2}}) + 2

\frac{2 s + 3}{s ^{2} + 6 s + 13}

\frac{x}{x - 2}

\frac{d}{d x} (\frac{2 x}{3} + (x + 1)^{\frac{2}{3}})

\frac{1}{5} \frac{d y}{d x} = (\frac{1}{5})^{2} - \frac{1}{5}

\frac{d}{d x} (y + x cos (y))

What is the solution for (dy)/(dx)=(x-1)/(x+3)(y-2)/(y-3) ?
The solution for (dy)/(dx)=(x-1)/(x+3)(y-2)/(y-3) is y=-\W(-((x+3)^4)/(e^{-c_{1)+x-2}})+2