What is the integral of (e^{ln(x)})/(x^2) ?

The integral of (e^{ln(x)})/(x^2) is ln|x|+C

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integral of (e^{ln(x)})/(x^2)

\int \frac{e ^{l n (x)}}{x ^{2}} d x

ln ∣ x ∣ + C

Solution steps

\int \frac{e ^{l n (x)}}{x ^{2}} d x

Simplify

\frac{e ^{l n (x)}}{x ^{2}} : \frac{1}{x}

= \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= ln ∣ x ∣

Add a constant to the solution

= ln ∣ x ∣ + C

\frac{d}{d x} (\frac{x ^{2} - 5 x}{x + 1})

x \to 4 lim (x 20 - x^{2})

\frac{\partial}{\partial x} (12 x y^{2})

\int_{0}^{1} ((x^{2} + 1) e^{- x}) d x

f (x) = cos (\frac{π}{x})

What is the integral of (e^{ln(x)})/(x^2) ?
The integral of (e^{ln(x)})/(x^2) is ln|x|+C