What is (\partial)/(\partial x)((x-2)^2+(y-2)^2) ?

The answer to (\partial)/(\partial x)((x-2)^2+(y-2)^2) is 2x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((x-2)^2+(y-2)^2)

\frac{\partial}{\partial x} ((x - 2)^{2} + (y - 2)^{2})

2 x - 4

Solution steps

\frac{\partial}{\partial x} ((x - 2)^{2} + (y - 2)^{2})

Simplify

(x - 2)^{2} + (y - 2)^{2} : x^{2} - 4 x + y^{2} + 8 - 4 y

= \frac{\partial}{\partial x} (x^{2} - 4 x + y^{2} + 8 - 4 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (4 x) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (8) - \frac{\partial}{\partial x} (4 y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (8) = 0

\frac{\partial}{\partial x} (4 y) = 0

= 2 x - 4 + 0 + 0 - 0

Simplify

= 2 x - 4

\int e^{x} + e d x

y = - 2 t^{2} + 3 t - 6

\frac{\partial}{\partial s} (r + s)

\int \frac{tan ( x )}{sec ( x )} d x

\frac{d}{d x} (\frac{2 x}{1 - tan ( x )})

What is (\partial)/(\partial x)((x-2)^2+(y-2)^2) ?
The answer to (\partial)/(\partial x)((x-2)^2+(y-2)^2) is 2x-4