What is the solution for x^2y^'+2xy=ln(x) ?

The solution for x^2y^'+2xy=ln(x) is y=(ln(x))/x-1/x+(c_{1})/(x^2)

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x^2y^'+2xy=ln(x)

x^{2} y^{^{'}} + 2 x y = ln (x)

y = \frac{ln ( x )}{x} - \frac{1}{x} + \frac{c _{1}}{x ^{2}}

Solution steps

x^{2} y^{'} (x) + 2 x y = ln (x)

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y = \frac{ln ( x )}{x} - \frac{1}{x} + \frac{c _{1}}{x ^{2}}

y = \frac{ln ( x )}{x} - \frac{1}{x} + \frac{c _{1}}{x ^{2}}

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What is the solution for x^2y^'+2xy=ln(x) ?
The solution for x^2y^'+2xy=ln(x) is y=(ln(x))/x-1/x+(c_{1})/(x^2)