What is the solution for (sqrt(x^4+1))/y (dy}{dx}=-\frac{x^3)/4 ?

The solution for (sqrt(x^4+1))/y (dy}{dx}=-\frac{x^3)/4 is y=e^{-1/8 sqrt(x^4+1)+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sqrt(x^4+1))/y (dy}{dx}=-\frac{x^3)/4

\frac{x ^{4} + 1}{y} \frac{d y}{d x} = - \frac{x ^{3}}{4}

y = e^{- \frac{1}{8} x^{4} + 1 + c_{1}}

Solution steps

\frac{x ^{4} + 1}{y} \frac{d y}{d x} = - \frac{x ^{3}}{4}

Solve separable ODE:

y = e^{- \frac{1}{8} x^{4} + 1 + c_{1}}

y = e^{- \frac{1}{8} x^{4} + 1 + c_{1}}

\frac{d ^{4}}{d x ^{4}} (e^{4 x})

(x e^{- x})^{^{'}}

\int_{0}^{2 π} 20 + 16 t^{2} d t

\int sin (1) d x

x^{3} - 6 x^{2} + 8 x, [2, 4]

What is the solution for (sqrt(x^4+1))/y (dy}{dx}=-\frac{x^3)/4 ?
The solution for (sqrt(x^4+1))/y (dy}{dx}=-\frac{x^3)/4 is y=e^{-1/8 sqrt(x^4+1)+c_{1}}