What is the integral from-infinity to-1 of e^{-34x} ?

The integral from-infinity to-1 of e^{-34x} is diverges

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integral from-infinity to-1 of e^{-34x}

\int_{- \infty}^{- 1} e^{- 34 x} d x

diverges

Solution steps

\int_{- \infty}^{- 1} e^{- 34 x} d x

Compute the indefinite integral:

\int e^{- 34 x} d x = - \frac{1}{34} e^{- 34 x} + C

Compute the boundaries:

\int_{- \infty}^{- 1} e^{- 34 x} d x =

diverges

= diverges

\int \frac{sin ( x )}{cos ^{9} ( x )} d x

\int_{- 1}^{7} - x^{2} + 6 x + 7 d x

x \to - 1 lim (t^{2} - x^{2})

\int \frac{( x ^{2} - 3 x - 7 )}{( 2 x + 3 ) ( x + 1 ) ^{2}} d x

\frac{\partial}{\partial x} (x^{3} e^{- 3 y})

What is the integral from-infinity to-1 of e^{-34x} ?
The integral from-infinity to-1 of e^{-34x} is diverges