What is the derivative of f(x)=(x^2+8)/(9x-2) ?

The derivative of f(x)=(x^2+8)/(9x-2) is (9x^2-4x-72)/((9x-2)^2)

What is the first derivative of f(x)=(x^2+8)/(9x-2) ?

The first derivative of f(x)=(x^2+8)/(9x-2) is (9x^2-4x-72)/((9x-2)^2)

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derivative of

f (x) = \frac{x ^{2} + 8}{9 x - 2}

\frac{9 x ^{2} - 4 x - 72}{( 9 x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 8}{9 x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 8 ) ( 9 x - 2 ) - \frac{d}{d x} ( 9 x - 2 ) ( x ^{2} + 8 )}{( 9 x - 2 ) ^{2}}

\frac{d}{d x} (x^{2} + 8) = 2 x

\frac{d}{d x} (9 x - 2) = 9

= \frac{2 x ( 9 x - 2 ) - 9 ( x ^{2} + 8 )}{( 9 x - 2 ) ^{2}}

Expand

2 x (9 x - 2) - 9 (x^{2} + 8) : 9 x^{2} - 4 x - 72

= \frac{9 x ^{2} - 4 x - 72}{( 9 x - 2 ) ^{2}}

\frac{d}{d x} (x arccos (x) - 1 - x^{2})

x^{10} e^{x}

e^{\frac{x}{2}}

\frac{d}{d x} (ux)

\int_{0}^{9} 5 x + 6 - x d x

What is the derivative of f(x)=(x^2+8)/(9x-2) ?
The derivative of f(x)=(x^2+8)/(9x-2) is (9x^2-4x-72)/((9x-2)^2)
What is the first derivative of f(x)=(x^2+8)/(9x-2) ?
The first derivative of f(x)=(x^2+8)/(9x-2) is (9x^2-4x-72)/((9x-2)^2)