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Popular >

y^'=-y^2t-y^2t^2

Solution

y^{^{'}} = - y^{2} t - y^{2} t^{2}

Solution

y = - \frac{6}{- 2 t ^{3} - 3 t ^{2} + c _{1}}

Solution steps

y^{'} (t) = - y^{2} t - y^{2} t^{2}

Solve separable ODE:

y = - \frac{6}{- 2 t ^{3} - 3 t ^{2} + c _{1}}

y = - \frac{6}{- 2 t ^{3} - 3 t ^{2} + c _{1}}

Popular Examples

slope of (0,3),(1,0)slope

(0, 3), (1, 0)

area y=14-x^2,y=x^2-4 area

y = 14 - x^{2}, y = x^{2} - 4

(\partial)/(\partial x)(5(y+3)(x-5)^3)

\frac{\partial}{\partial x} (5 (y + 3) (x - 5)^{3})

integral of (x^2)/((x-6)(x-7)^2)

\int \frac{x ^{2}}{( x - 6 ) ( x - 7 ) ^{2}} d x

laplacetransform te^{7t}laplace transform

t e^{7 t}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y^2t-y^2t^2 ?
The solution for y^'=-y^2t-y^2t^2 is y=-6/(-2t^3-3t^2+c_{1)}