What is the solution for 6(dy)/(dx)-2y=xy^4,y(0)=-2 ?

The solution for 6(dy)/(dx)-2y=xy^4,y(0)=-2 is y=(2\sqrt[3]{e^x})/(\sqrt[3]{-4e^xx+4e^x-5)}

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6(dy)/(dx)-2y=xy^4,y(0)=-2

6 \frac{d y}{d x} - 2 y = x y^{4}, y (0) = - 2

Solution steps

6 \frac{d y}{d x} - 2 y = x y^{4}

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What is the solution for 6(dy)/(dx)-2y=xy^4,y(0)=-2 ?
The solution for 6(dy)/(dx)-2y=xy^4,y(0)=-2 is y=(2\sqrt[3]{e^x})/(\sqrt[3]{-4e^xx+4e^x-5)}