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Popular >

((x-4)^2)^'

Solution

((x - 4)^{2})^{^{'}}

Solution

2 (x - 4)

Solution steps

((x - 4)^{2})^{'}

Apply the chain rule:

2 (x - 4) (x - 4)^{'}

= 2 (x - 4) (x - 4)^{'}

(x - 4)^{'} = 1

= 2 (x - 4) \cdot 1

Simplify

= 2 (x - 4)

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integral from 0 to 4 of x/(x^2-1)

\int_{0}^{4} \frac{x}{x ^{2} - 1} d x

(\partial)/(\partial x)(sqrt(3x+2y-3))

\frac{\partial}{\partial x} (3 x + 2 y - 3)

area y=x^2,y=3-x,(0,1.3)area

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Frequently Asked Questions (FAQ)

What is the ((x-4)^2)^' ?
The ((x-4)^2)^' is 2(x-4)
What is the first ((x-4)^2)^' ?
The first ((x-4)^2)^' is 2(x-4)