What is the solution for y^'=18.2-0.7y ?

The solution for y^'=18.2-0.7y is y=-(e^{-0.7t-c_{1}})/(0.7)+(18.2)/(0.7)

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y^'=18.2-0.7y

y^{^{'}} = 18.2 - 0.7 y

y = - \frac{e ^{- 0.7 t - c_{1}}}{0.7} + \frac{18.2}{0.7}

Solution steps

y^{'} (t) = 18.2 - 0.7 y

Solve separable ODE:

y = - \frac{e ^{- 0.7 t - c_{1}}}{0.7} + \frac{18.2}{0.7}

y = - \frac{e ^{- 0.7 t - c_{1}}}{0.7} + \frac{18.2}{0.7}

y^{^{'}} = 1 - \frac{2 y}{100 + 2 x}, y (0) = 20

t^{2} y^{^{'}} + y = 0

x \to 4 lim (x)

\frac{s + 3}{( s + 3 ) ^{2} + 4}

\frac{d}{d x} (\frac{1}{2} cos (\frac{x}{2}))

What is the solution for y^'=18.2-0.7y ?
The solution for y^'=18.2-0.7y is y=-(e^{-0.7t-c_{1}})/(0.7)+(18.2)/(0.7)