What is the integral from-7 to 7 of 1/x ?

The integral from-7 to 7 of 1/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-7 to 7 of 1/x

\int_{- 7}^{7} \frac{1}{x} d x

diverges

Solution steps

\int_{- 7}^{7} \frac{1}{x} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 7}^{0} \frac{1}{x} d x + \int_{0}^{7} \frac{1}{x} d x

\int_{- 7}^{0} \frac{1}{x} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

x \to 2 lim (3 ln (x - 1))

y = \frac{x}{9 + x ^{2}}, (0, 0)

\int 40 sin (\frac{π x}{3}) + 50 d x

\int 3 + x \cdot (x + 1)^{2} d x

\frac{\partial}{\partial x} (x^{\frac{1}{2}})

What is the integral from-7 to 7 of 1/x ?
The integral from-7 to 7 of 1/x is diverges