What is the integral of sqrt(4)-x^2 ?

The integral of sqrt(4)-x^2 is 2x-(x^3)/3+C

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integral of sqrt(4)-x^2

\int 4 - x^{2} d x

2 x - \frac{x ^{3}}{3} + C

Solution steps

\int 4 - x^{2} d x

4 = 2

= \int 2 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x - \int x^{2} d x

\int 2 d x = 2 x

\int x^{2} d x = \frac{x ^{3}}{3}

= 2 x - \frac{x ^{3}}{3}

Add a constant to the solution

= 2 x - \frac{x ^{3}}{3} + C

0.81 t^{2}

\int x e^{11 x} d x

f (x) = x^{- 11}

3 cos (π x), 12 x^{2} - 3, - 0.5, 0.5

x = y^{2} - 1, x = 7 - y^{2}

What is the integral of sqrt(4)-x^2 ?
The integral of sqrt(4)-x^2 is 2x-(x^3)/3+C