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Popular >

y^'=(y^2+2xy)/(x^2)

Solution

y^{^{'}} = \frac{y ^{2} + 2 x y}{x ^{2}}

Solution

y = \frac{x ^{2}}{- x + c _{1}}

Solution steps

y^{'} (x) = \frac{y ^{2} + 2 x y}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x ^{2}}{- x + c _{1}}

y = \frac{x ^{2}}{- x + c _{1}}

Popular Examples

integral from 0 to pi/2 of 4cos^5(x)

\int_{0}^{\frac{π}{2}} 4 cos^{5} (x) d x

3y^{''}-6y^'+3y=0

3 y^{^{''}} - 6 y^{^{'}} + 3 y = 0

(\partial)/(\partial y)((2x^2y)/(3+x^2y^2))

\frac{\partial}{\partial y} (\frac{2 x ^{2} y}{3 + x ^{2} y ^{2}})

integral of (e^t)/(1+e^t)

\int \frac{e ^{t}}{1 + e ^{t}} d t

sum from n=0 to infinity of (0.5)^n

n = 0 \sum \infty (0.5)^{n}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y^2+2xy)/(x^2) ?
The solution for y^'=(y^2+2xy)/(x^2) is y=(x^2)/(-x+c_{1)}