What is the derivative of 4x^3-16x ?

The derivative of 4x^3-16x is 12x^2-16

What is the first derivative of 4x^3-16x ?

The first derivative of 4x^3-16x is 12x^2-16

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derivative of

4 x^{3} - 16 x

12 x^{2} - 16

Solution steps

\frac{d}{d x} (4 x^{3} - 16 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (16 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (16 x) = 16

= 12 x^{2} - 16

\frac{d x}{d t} - 4 x = cos (4 t)

\int 8 sin (- 2 t + 7) d t

(- 3) (0.1)

f (t) = e^{t} sin (t)

5 x, x^{2} - 6, 0

What is the derivative of 4x^3-16x ?
The derivative of 4x^3-16x is 12x^2-16
What is the first derivative of 4x^3-16x ?
The first derivative of 4x^3-16x is 12x^2-16