What is the integral from 0.1 to 0.2 of 400x ?

The integral from 0.1 to 0.2 of 400x is 6

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integral from 0.1 to 0.2 of 400x

\int_{0.1}^{0.2} 400 x d x

6

Solution steps

\int_{0.1}^{0.2} 400 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 400 \cdot \int_{0.1}^{0.2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0.1}^{0.2}

= 400 [\frac{x ^{2}}{2}]_{0.1}^{0.2}

Simplify

= 400 [0.5 x^{2}]_{0.1}^{0.2}

Compute the boundaries:

0.015

= 400 \cdot 0.015

Simplify

= 6

\int_{0}^{l n (3)} e^{x} - e^{- 2 x} d x

\frac{d y}{d x} + \frac{2}{x} y = 6 x^{4} y^{2}

\frac{d y}{d x} = \frac{y}{x + 2 y}

4 e^{x + 4} + 1

x \to \infty + lim (f (x))

What is the integral from 0.1 to 0.2 of 400x ?
The integral from 0.1 to 0.2 of 400x is 6