What is the integral of e^{-10t} ?

The integral of e^{-10t} is -1/10 e^{-10t}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{-10t}

\int e^{- 10 t} d t

- \frac{1}{10} e^{- 10 t} + C

Solution steps

\int e^{- 10 t} d t

Apply u-substitution

: \int - \frac{1}{10} e^{u} d u

= \int - \frac{1}{10} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{10} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - \frac{1}{10} e^{u}

Substitute back

u = - 10 t

= - \frac{1}{10} e^{- 10 t}

Add a constant to the solution

= - \frac{1}{10} e^{- 10 t} + C

\frac{\partial}{\partial y} (x^{2} + y^{3})

\frac{d}{d x} (\frac{1 - 4 x}{5 + x})

\frac{d}{d x} (3 x^{2} - 4 x + 6)

y \to - 3 lim (y)

\int - e^{- 2 y} d y