What is area y=5cos(x),y=5sin(x) ?

The answer to area y=5cos(x),y=5sin(x) is 10sqrt(2)

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area y=5cos(x),y=5sin(x)

area

y = 5 cos (x), y = 5 sin (x)

102

Decimal Notation

14.14213 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{4}}^{\frac{5 π}{4}} ∣ 5 cos (x) - 5 sin (x) ∣ d x

Solve

\int_{\frac{π}{4}}^{\frac{5 π}{4}} ∣ 5 cos (x) - 5 sin (x) ∣ d x : 102

The area is:

= 102

\int - \frac{2}{x + 2} d x

\frac{\partial}{\partial x} (x^{2} y^{2} - x)

\int sin^{2} (4 x) \cdot cos^{3} (4 x) d x

\frac{d}{d x} (ln^{2} (3) \cdot 3^{x})

x \to 2 lim (\frac{3 x - 2}{1 - 2 x})

What is area y=5cos(x),y=5sin(x) ?
The answer to area y=5cos(x),y=5sin(x) is 10sqrt(2)