What is the tangent of-2x^2,\at x=1 ?

The tangent of-2x^2,\at x=1 is y=-4x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of-2x^2,\at x=1

tangent of

- 2 x^{2}, at x = 1

y = - 4 x + 2

Solution steps

Find the tangent point:

(1, - 2)

Find the slope of

y = - 2 x^{2} : \frac{d y}{d x} = - 4 x

Compute the slope of

y = - 2 x^{2}

x = 1 : m = - 4

Find the line with slope m=

- 4

and passing through

(1, - 2) : y = - 4 x + 2

y = - 4 x + 2

y = sin (e^{x})

x \to \infty lim (- x e^{1 - x})

\int \frac{7 r ^{2}}{r + 3} d r

2 x^{2} - 9 x + 10, at x = 1

\int \frac{( 1 - 2 y )}{y} d y